{"id":727,"date":"2025-12-21T00:17:48","date_gmt":"2025-12-20T21:17:48","guid":{"rendered":"https:\/\/dersegeldim.com\/kimya\/?p=727"},"modified":"2025-12-21T23:04:37","modified_gmt":"2025-12-21T20:04:37","slug":"1-1-5-kimyasal-sitokiyometrik-hesaplamalar","status":"publish","type":"post","link":"https:\/\/dersegeldim.com\/kimya\/tyt-kimya\/kimya-10\/etkilesim-kimya-10\/1-1-5-kimyasal-sitokiyometrik-hesaplamalar\/","title":{"rendered":"1.1.5. Kimyasal (Sitokiyometrik) Hesaplamalar"},"content":{"rendered":"\n
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DERS<\/p>\n\n\n\n

<\/div>\n\n\n\n

K\u0130MYA 10<\/p>\n\n\n\n

1. TEMA<\/p>\n\n\n\n

ETK\u0130LE\u015e\u0130M<\/p>\n\n\n\n

<\/div>\n<\/div>\n\n\n\n
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KONU<\/p>\n\n\n\n

<\/div>\n\n\n\n

1. B\u00d6L\u00dcM:
1.1. Kimyasal Tepkimeler<\/p>\n\n\n\n

1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar<\/strong><\/p>\n\n\n\n

<\/div>\n<\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n
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1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar<\/h2>\n\n\n\n
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  • Denkle\u015ftirilmemi\u015f <\/strong>bir tepkimede hesap yap\u0131lamaz.<\/strong><\/li>\n\n\n\n
  • Denkle\u015fmi\u015f bir tepkimede katsay\u0131lar<\/strong>:\n
      \n
    • mol say\u0131lar\u0131n\u0131n oran\u0131n\u0131 verir.<\/strong><\/li>\n\n\n\n
    • B\u00fct\u00fcn hesaplar bu oranlara g\u00f6re yap\u0131l\u0131r.<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div>\n\n\n\n
      \n

      Mesela:<\/h3>\n\n\n\n

      4A(g)<\/sub> + 2B(g)<\/sub> \u2192 3C(g)<\/sub><\/strong><\/p>\n\n\n\n

      Tepkimesinde:<\/p>\n\n\n\n

      \n
      \n
        \n
      • 4 mol A<\/em><\/strong> girerse:\n
          \n
        • 2 mol B<\/em><\/strong> girer<\/li>\n\n\n\n
        • 3 mol C<\/strong> <\/em>olu\u015fur.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div>\n\n\n\n
          \n
            \n
          • 8 mol A<\/em><\/strong> girerse:\n
              \n
            • 4 mol B<\/em><\/strong> girer.<\/li>\n\n\n\n
            • 6 mol C<\/em><\/strong> olu\u015fur.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n
              \n

              1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar<\/h2>\n\n\n\n

              Tam verimle <\/strong>ger\u00e7ekle\u015fen tepkimelerde girenlerden en az biri biter.<\/strong><\/p>\n\n\n\n

              \n
              \n

              \u00d6rnek:<\/h3>\n\n\n\n

              3H2<\/sub> + N2<\/sub> \u2192 2NH3<\/sub><\/strong><\/p>\n\n\n\n

              Yukar\u0131daki tepkimeye g\u00f6re:<\/strong><\/p>\n\n\n\n

                \n
              • 6 mol H2<\/sub> tam verimle tepkimeye girerse ka\u00e7 mol N2<\/sub> ile tepkime verir?<\/strong><\/li>\n\n\n\n
              • Tam verimle ger\u00e7ekle\u015fen tepkimede 8 mol NH3<\/sub> (Amonyak) olu\u015fmas\u0131 i\u00e7in ka\u00e7 mol H2<\/sub> kullan\u0131lmal\u0131d\u0131r?<\/strong><\/li>\n\n\n\n
              • 56 gram N2<\/sub> nin tam verimle tepkimesinden ka\u00e7 gram NH3<\/sub> olu\u015fur?<\/strong><\/li>\n\n\n\n
              • 6 gram H2<\/sub> ve 14 gram N2<\/sub> nin tam verimli tepkimesinden hangi madde ka\u00e7 gram artar?<\/strong> (N2<\/sub>: 28, H2<\/sub>: 2, NH3<\/sub>: 17)<\/li>\n<\/ul>\n<\/div>\n\n\n\n
                <\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n
                \n

                1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar<\/h2>\n\n\n\n
                \n
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                \u00d6rnek:<\/h3>\n\n\n\n

                Zn(k)<\/sub>\u00a0+ 2HCl(suda)<\/sub>\u00a0\u2192\u00a0ZnCl2(suda)<\/sub> + H2(g)<\/sub><\/strong><\/p>\n\n\n\n

                tepkimesine g\u00f6re \u00e7inkonun tuz ruhu ile tepkimeye girmesiyle hidrojen gaz\u0131 olu\u015fur.<\/p>\n\n\n\n

                Tam verimle ger\u00e7ekle\u015fen tepkimede ba\u015flang\u0131\u00e7ta 260 g Zn ve 146 g HCl al\u0131n\u0131rsa hangi maddeden ka\u00e7 g artar?<\/strong> (H: 1 g\/mol, Cl: 35,5 g\/mol, Zn: 65 g\/mol)<\/p>\n<\/div>\n\n\n\n

                <\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n
                \n

                3. Y\u00fczde Verim Sorular\u0131<\/h2>\n\n\n\n
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                Y\u00fczde Verim Nedir?<\/h3>\n\n\n\n
                  \n
                • Ger\u00e7ekte<\/em><\/strong>, bir \u00e7ok tepkime, tam (%100) verimle ger\u00e7ekle\u015fmez<\/em><\/strong>.<\/li>\n\n\n\n
                • Bir \u00e7ok tepkimede, beklenenden daha az \u00fcr\u00fcn<\/strong> olu\u015fur.\n
                    \n
                  • Tam verime g\u00f6re hesaplanan \u00fcr\u00fcn miktar\u0131na teorik (kuramsal) verim<\/strong> denir.<\/li>\n\n\n\n
                  • Tepkimede olu\u015fan \u00fcr\u00fcn<\/em><\/strong> miktar\u0131na da ger\u00e7ek verim<\/strong> denir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n
                      \n
                    • Bir tepkimenin y\u00fczde verimi, \u015fu form\u00fcl ile hesaplan\u0131r:<\/strong><\/li>\n<\/ul>\n\n\n\n

                      % verim = ger\u00e7ek verim<\/span> <\/span> teorik verim<\/span><\/span> x 100<\/span><\/p>\n<\/div>\n\n\n\n

                      \n

                      \u00d6rnek:<\/h3>\n\n\n\n

                      Hesaplamalara g\u00f6re bir tepkime, tam verimle ger\u00e7ekle\u015fti\u011finde 8 gram \u00fcr\u00fcn olu\u015fmas\u0131 gerekiyor. Fakat, ayn\u0131 tepkimeden elde edilen \u00fcr\u00fcn 6,4 gramda kalm\u0131\u015ft\u0131r.<\/p>\n\n\n\n

                      Buna g\u00f6re, bu tepkimenin verimi y\u00fczde ka\u00e7t\u0131rr?<\/strong><\/p>\n<\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n

                      \n

                      3. Y\u00fczde Verim Sorular\u0131<\/h2>\n\n\n\n
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                      \u00d6rnek:<\/h3>\n\n\n\n

                      16 gram k\u00fck\u00fcrt (S) yand\u0131\u011f\u0131nda, NK\u2019da 8,96 litre SO2<\/sub> elde ediliyor.<\/p>\n\n\n\n

                      Tepkimenin y\u00fczde verimi ka\u00e7t\u0131r? (S: 32 g\/mol)<\/strong><\/p>\n<\/div>\n\n\n\n

                      <\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n
                      \n

                      3. Y\u00fczde Verim Sorular\u0131<\/h2>\n\n\n\n
                      \n
                      \n

                      \u00d6rnek:<\/h3>\n\n\n\n

                      4NH3(g)<\/sub> + 3O2(g)<\/sub> \u2192 2N2(g)<\/sub> + 6H2<\/sub>O(s)<\/sub><\/strong><\/p>\n\n\n\n

                      Bu tepkimeye g\u00f6re 1 mol amonyak ile 0,75 mol oksijen gaz\u0131n\u0131n tepkimesinden 5,6 g azot gaz\u0131 olu\u015fmu\u015ftur.<\/p>\n\n\n\n

                      Tepkimenin y\u00fczde verimini hesaplay\u0131n\u0131z.<\/strong> (N: 14 g\/mol)<\/p>\n<\/div>\n\n\n\n

                      <\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n
                      \n
                      \"\"<\/span>
                      \n

                      1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar<\/strong><\/p>\n\n\n\n

                      Bitti \ud83d\ude41<\/p>\n<\/div><\/div>\n<\/div><\/div>\n","protected":false},"excerpt":{"rendered":"

                      DERS K\u0130MYA 10 1. TEMA ETK\u0130LE\u015e\u0130M KONU 1. B\u00d6L\u00dcM:1.1. Kimyasal Tepkimeler 1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar 1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar Mesela: 4A(g) + 2B(g) \u2192 3C(g) Tepkimesinde: 1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar Tam verimle ger\u00e7ekle\u015fen tepkimelerde girenlerden en az biri biter. \u00d6rnek: 3H2 + N2 \u2192 2NH3 Yukar\u0131daki tepkimeye g\u00f6re: 1.1.5. Kimyasal (Stokiyometrik) Hesaplamalar \u00d6rnek: Zn(k)\u00a0+ 2HCl(suda)\u00a0\u2192\u00a0ZnCl2(suda) + H2(g) tepkimesine g\u00f6re \u00e7inkonun tuz […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"dcnnt-slider-with-pen-tool.php","format":"standard","meta":{"footnotes":""},"categories":[4],"tags":[],"class_list":["post-727","post","type-post","status-publish","format-standard","hentry","category-etkilesim-kimya-10"],"_links":{"self":[{"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/posts\/727","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/comments?post=727"}],"version-history":[{"count":49,"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/posts\/727\/revisions"}],"predecessor-version":[{"id":806,"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/posts\/727\/revisions\/806"}],"wp:attachment":[{"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/media?parent=727"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/categories?post=727"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/dersegeldim.com\/kimya\/wp-json\/wp\/v2\/tags?post=727"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}